8 original questions from New Regents. The worksheet, answer key, and browser practice are free.
Catalysts and Activation Energy 4 questions
Catalysts and Activation Energy
New Regents original practice • Name: ____________________ Date: __________ Show your work for written answers.
On a potential energy diagram, the forward activation energy is the difference between the peak and reactants. The net energy change is products minus reactants.
Question 1
Which change explains why a catalyst can increase reaction rate?
- It provides a pathway with a lower activation energy.
- It increases the number of atoms in the reactants.
- It always increases the net energy released per mole.
- It removes the need for reactant particles to interact.
Question 2
Two pathways connect the same reactants and products, but one has a lower peak. Explain why they have the same net energy change.
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Question 3
Reactants have a potential energy of 25 kJ/mol and a pathway peaks at 85 kJ/mol. Calculate the forward activation energy.
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Question 4
Which statement describes the effect of a catalyst at a fixed temperature?
- It raises the average kinetic energy of all reactants.
- It raises the minimum energy needed for reaction.
- It lets more particles reach the energy threshold for reaction.
- It makes every collision produce a reaction.
Two Paths to the Same Products 4 questions
Two Paths to the Same Products
Use the information below to answer the questions.
A simulation shows two pathways for the same reaction. Both begin at the reactant energy level and end at the product energy level.
Question 5
Which pathway represents the catalyzed reaction?
- Path A, because it has a higher peak.
- Path B, because it has a lower peak.
- Path A, because it has a lower product energy.
- Both, because they have identical barriers.
Question 6
Use the graph to calculate the forward activation energy of each path.
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Question 7
What is the net energy change for the reaction in the graph?
- −80 kJ/mol
- −20 kJ/mol
- +20 kJ/mol
- +60 kJ/mol
Question 8
Which path also has a smaller activation energy for the reverse reaction? Use the graph to justify your answer.
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